0=ln(4-x)+1

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Solution for 0=ln(4-x)+1 equation:


Simplifying
0 = ln(4 + -1x) + 1
0 = (4 * ln + -1x * ln) + 1
0 = (4ln + -1lnx) + 1

Reorder the terms:
0 = 1 + 4ln + -1lnx

Solving
0 = 1 + 4ln + -1lnx

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-4ln' to each side of the equation.
0 + -4ln = 1 + 4ln + -4ln + -1lnx
Remove the zero:
-4ln = 1 + 4ln + -4ln + -1lnx

Combine like terms: 4ln + -4ln = 0
-4ln = 1 + 0 + -1lnx
-4ln = 1 + -1lnx

Add 'lnx' to each side of the equation.
-4ln + lnx = 1 + -1lnx + lnx

Combine like terms: -1lnx + lnx = 0
-4ln + lnx = 1 + 0
-4ln + lnx = 1

Reorder the terms:
-1 + -4ln + lnx = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -4ln + lnx = 0

The solution to this equation could not be determined.

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