0=j/40-3

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Solution for 0=j/40-3 equation: 



0=j/40-3

We move all terms to the left:

0-(j/40-3)=0

We add all the numbers together, and all the variables

-(j/40-3)=0

We get rid of parentheses

-j/40+3=0

We multiply all the terms by the denominator


-j+3*40=0

We add all the numbers together, and all the variables

-1j+120=0

We move all terms containing j to the left, all other terms to the right

-j=-120

j=-120/-1

j=+120

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