0=9(k2/3)+33

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Solution for 0=9(k2/3)+33 equation: 


k in (-oo:+oo)

0 = 9*((k^2)/3)+33 // - 9*((k^2)/3)+33

0-(9*((k^2)/3))-33 = 0

-3*k^2-33 = 0

-3*k^2 = 33 // : -3

k^2 = -11

k belongs to the empty set

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