0=8y(y+6)

Solution for 0=8y(y+6) equation:

0=8y(y+6)

We move all terms to the left:

0-(8y(y+6))=0

We add all the numbers together, and all the variables

-(8y(y+6))=0


We calculate terms in parentheses: -(8y(y+6)), so:

8y(y+6)

We multiply parentheses

8y^2+48y

Back to the equation:

-(8y^2+48y)


We get rid of parentheses

-8y^2-48y=0

a = -8; b = -48; c = 0;
Δ = b2-4ac
Δ = -482-4·(-8)·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-48}{2*-8}=\frac{0}{-16}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+48}{2*-8}=\frac{96}{-16}
=-6
$