0=8t(-2t+10)

Solution for 0=8t(-2t+10) equation:

0=8t(-2t+10)

We move all terms to the left:

0-(8t(-2t+10))=0

We add all the numbers together, and all the variables

-(8t(-2t+10))=0


We calculate terms in parentheses: -(8t(-2t+10)), so:

8t(-2t+10)

We multiply parentheses

-16t^2+80t

Back to the equation:

-(-16t^2+80t)


We get rid of parentheses

16t^2-80t=0

a = 16; b = -80; c = 0;
Δ = b2-4ac
Δ = -802-4·16·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-80}{2*16}=\frac{0}{32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+80}{2*16}=\frac{160}{32}
=5
$