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0=5x^2-9x-5
We move all terms to the left:
0-(5x^2-9x-5)=0
We add all the numbers together, and all the variables
-(5x^2-9x-5)=0
We get rid of parentheses
-5x^2+9x+5=0
a = -5; b = 9; c = +5;
Δ = b2-4ac
Δ = 92-4·(-5)·5
Δ = 181
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{181}}{2*-5}=\frac{-9-\sqrt{181}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{181}}{2*-5}=\frac{-9+\sqrt{181}}{-10} $
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