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0=5x^2+40x+100
We move all terms to the left:
0-(5x^2+40x+100)=0
We add all the numbers together, and all the variables
-(5x^2+40x+100)=0
We get rid of parentheses
-5x^2-40x-100=0
a = -5; b = -40; c = -100;
Δ = b2-4ac
Δ = -402-4·(-5)·(-100)
Δ = -400
Delta is less than zero, so there is no solution for the equation
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