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0=5x^2+12x+20
We move all terms to the left:
0-(5x^2+12x+20)=0
We add all the numbers together, and all the variables
-(5x^2+12x+20)=0
We get rid of parentheses
-5x^2-12x-20=0
a = -5; b = -12; c = -20;
Δ = b2-4ac
Δ = -122-4·(-5)·(-20)
Δ = -256
Delta is less than zero, so there is no solution for the equation
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