0=4x2+33x-27

Solution for 0=4x2+33x-27 equation:

0=4x^2+33x-27

We move all terms to the left:

0-(4x^2+33x-27)=0

We add all the numbers together, and all the variables

-(4x^2+33x-27)=0

We get rid of parentheses

-4x^2-33x+27=0

a = -4; b = -33; c = +27;
Δ = b2-4ac
Δ = -332-4·(-4)·27
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-39}{2*-4}=\frac{-6}{-8}
=3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+39}{2*-4}=\frac{72}{-8}
=-9
$