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0=4x(3x-6)
We move all terms to the left:
0-(4x(3x-6))=0
We add all the numbers together, and all the variables
-(4x(3x-6))=0
We calculate terms in parentheses: -(4x(3x-6)), so:We get rid of parentheses
4x(3x-6)
We multiply parentheses
12x^2-24x
Back to the equation:
-(12x^2-24x)
-12x^2+24x=0
a = -12; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-12)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-12}=\frac{-48}{-24} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-12}=\frac{0}{-24} =0 $
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