0=4x(22-x)

Solution for 0=4x(22-x) equation:

0=4x(22-x)

We move all terms to the left:

0-(4x(22-x))=0

We add all the numbers together, and all the variables

-(4x(-1x+22))+0=0

We add all the numbers together, and all the variables

-(4x(-1x+22))=0


We calculate terms in parentheses: -(4x(-1x+22)), so:

4x(-1x+22)

We multiply parentheses

-4x^2+88x

Back to the equation:

-(-4x^2+88x)


We get rid of parentheses

4x^2-88x=0

a = 4; b = -88; c = 0;
Δ = b2-4ac
Δ = -882-4·4·0
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-88)-88}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-88)+88}{2*4}=\frac{176}{8}
=22
$