0=3x(20x-29)

Solution for 0=3x(20x-29) equation:

0=3x(20x-29)

We move all terms to the left:

0-(3x(20x-29))=0

We add all the numbers together, and all the variables

-(3x(20x-29))=0


We calculate terms in parentheses: -(3x(20x-29)), so:

3x(20x-29)

We multiply parentheses

60x^2-87x

Back to the equation:

-(60x^2-87x)


We get rid of parentheses

-60x^2+87x=0

a = -60; b = 87; c = 0;
Δ = b2-4ac
Δ = 872-4·(-60)·0
Δ = 7569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7569}=87$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(87)-87}{2*-60}=\frac{-174}{-120}
=1+9/20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(87)+87}{2*-60}=\frac{0}{-120}
=0
$