0=3(x+2)(x-2)

Solution for 0=3(x+2)(x-2) equation:

Simplifying
0 = 3(x + 2)(x + -2)

Reorder the terms:
0 = 3(2 + x)(x + -2)

Reorder the terms:
0 = 3(2 + x)(-2 + x)

Multiply (2 + x) * (-2 + x)
0 = 3(2(-2 + x) + x(-2 + x))
0 = 3((-2 * 2 + x * 2) + x(-2 + x))
0 = 3((-4 + 2x) + x(-2 + x))
0 = 3(-4 + 2x + (-2 * x + x * x))
0 = 3(-4 + 2x + (-2x + x2))

Combine like terms: 2x + -2x = 0
0 = 3(-4 + 0 + x2)
0 = 3(-4 + x2)
0 = (-4 * 3 + x2 * 3)
0 = (-12 + 3x2)

Solving
0 = -12 + 3x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x2' to each side of the equation.
0 + -3x2 = -12 + 3x2 + -3x2
Remove the zero:
-3x2 = -12 + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
-3x2 = -12 + 0
-3x2 = -12

Divide each side by '-3'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}