# 0=2x2-23x-39

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## Solution for 0=2x2-23x-39 equation:

0=2x^2-23x-39
We move all terms to the left:
0-(2x^2-23x-39)=0
We add all the numbers together, and all the variables
-(2x^2-23x-39)=0
We get rid of parentheses
-2x^2+23x+39=0
a = -2; b = 23; c = +39;Δ = b2-4acΔ = 232-4·(-2)·39Δ = 841The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-29}{2*-2}=\frac{-52}{-4} =+13$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+29}{2*-2}=\frac{6}{-4} =-1+1/2$

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