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0=2x^2-14x+9
We move all terms to the left:
0-(2x^2-14x+9)=0
We add all the numbers together, and all the variables
-(2x^2-14x+9)=0
We get rid of parentheses
-2x^2+14x-9=0
a = -2; b = 14; c = -9;
Δ = b2-4ac
Δ = 142-4·(-2)·(-9)
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{31}}{2*-2}=\frac{-14-2\sqrt{31}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{31}}{2*-2}=\frac{-14+2\sqrt{31}}{-4} $
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