0=2x2+6x-247

Solution for 0=2x2+6x-247 equation:

0=2x^2+6x-247

We move all terms to the left:

0-(2x^2+6x-247)=0

We add all the numbers together, and all the variables

-(2x^2+6x-247)=0

We get rid of parentheses

-2x^2-6x+247=0

a = -2; b = -6; c = +247;
Δ = b2-4ac
Δ = -62-4·(-2)·247
Δ = 2012
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2012}=\sqrt{4*503}=\sqrt{4}*\sqrt{503}=2\sqrt{503}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{503}}{2*-2}=\frac{6-2\sqrt{503}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{503}}{2*-2}=\frac{6+2\sqrt{503}}{-4}
$