0=27-9(k+3)

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Solution for 0=27-9(k+3) equation: 



0=27-9(k+3)

We move all terms to the left:

0-(27-9(k+3))=0

We add all the numbers together, and all the variables

-(27-9(k+3))=0



We calculate terms in parentheses: -(27-9(k+3)), so:

27-9(k+3)

determiningTheFunctionDomain
-9(k+3)+27

We multiply parentheses

-9k-27+27

We add all the numbers together, and all the variables

-9k

Back to the equation:

-(-9k)



We get rid of parentheses

9k=0

k=0/9

k=0

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