0=2(x2-4x-444)

Solution for 0=2(x2-4x-444) equation:

0=2(x2-4x-444)

We move all terms to the left:

0-(2(x2-4x-444))=0

We add all the numbers together, and all the variables

-(2(+x^2-4x-444))+0=0

We add all the numbers together, and all the variables

-(2(+x^2-4x-444))=0


We calculate terms in parentheses: -(2(+x^2-4x-444)), so:

2(+x^2-4x-444)

We multiply parentheses

2x^2-8x-888

Back to the equation:

-(2x^2-8x-888)


We get rid of parentheses

-2x^2+8x+888=0

a = -2; b = 8; c = +888;
Δ = b2-4ac
Δ = 82-4·(-2)·888
Δ = 7168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7168}=\sqrt{1024*7}=\sqrt{1024}*\sqrt{7}=32\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-32\sqrt{7}}{2*-2}=\frac{-8-32\sqrt{7}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+32\sqrt{7}}{2*-2}=\frac{-8+32\sqrt{7}}{-4}
$