0=2(k+2)+-2

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Solution for 0=2(k+2)+-2 equation:



0=2(k+2)+-2
We move all terms to the left:
0-(2(k+2)+-2)=0
We add all the numbers together, and all the variables
-(2(k+2)+-2)=0
We use the square of the difference formula
-(2(k+2)-2)=0
We calculate terms in parentheses: -(2(k+2)-2), so:
2(k+2)-2
We multiply parentheses
2k+4-2
We add all the numbers together, and all the variables
2k+2
Back to the equation:
-(2k+2)
We get rid of parentheses
-2k-2=0
We move all terms containing k to the left, all other terms to the right
-2k=2
k=2/-2
k=-1

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