0=16t2+101t+10

Solution for 0=16t2+101t+10 equation:

0=16t^2+101t+10

We move all terms to the left:

0-(16t^2+101t+10)=0

We add all the numbers together, and all the variables

-(16t^2+101t+10)=0

We get rid of parentheses

-16t^2-101t-10=0

a = -16; b = -101; c = -10;
Δ = b2-4ac
Δ = -1012-4·(-16)·(-10)
Δ = 9561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-101)-\sqrt{9561}}{2*-16}=\frac{101-\sqrt{9561}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-101)+\sqrt{9561}}{2*-16}=\frac{101+\sqrt{9561}}{-32}
$