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0=15-3(x-5)
We move all terms to the left:
0-(15-3(x-5))=0
We add all the numbers together, and all the variables
-(15-3(x-5))=0
We calculate terms in parentheses: -(15-3(x-5)), so:We get rid of parentheses
15-3(x-5)
determiningTheFunctionDomain -3(x-5)+15
We multiply parentheses
-3x+15+15
We add all the numbers together, and all the variables
-3x+30
Back to the equation:
-(-3x+30)
3x-30=0
We move all terms containing x to the left, all other terms to the right
3x=30
x=30/3
x=10
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