0=10(-2,5y)y

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Solution for 0=10(-2,5y)y equation: 



0=10(-2.5y)y

We move all terms to the left:

0-(10(-2.5y)y)=0

We add all the numbers together, and all the variables

-(10(-2.5y)y)=0



We calculate terms in parentheses: -(10(-2.5y)y), so:

10(-2.5y)y

We multiply parentheses

-20y^2

Back to the equation:

-(-20y^2)



We get rid of parentheses

20y^2=0

a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{40}=0$

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