0=1+2/9c-c

Solution for 0=1+2/9c-c equation:

0=1+2/9c-c

We move all terms to the left:

0-(1+2/9c-c)=0


Domain of the equation: 9c-c)!=0

c∈R


We add all the numbers together, and all the variables

-(-1c+2/9c+1)+0=0

We add all the numbers together, and all the variables

-(-1c+2/9c+1)=0

We get rid of parentheses

1c-2/9c-1=0

We multiply all the terms by the denominator


1c*9c-1*9c-2=0

Wy multiply elements

9c^2-9c-2=0

a = 9; b = -9; c = -2;
Δ = b2-4ac
Δ = -92-4·9·(-2)
Δ = 153
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{153}=\sqrt{9*17}=\sqrt{9}*\sqrt{17}=3\sqrt{17}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3\sqrt{17}}{2*9}=\frac{9-3\sqrt{17}}{18}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3\sqrt{17}}{2*9}=\frac{9+3\sqrt{17}}{18}
$