0=0.5p2-200

Solution for 0=0.5p2-200 equation:

0=0.5p^2-200

We move all terms to the left:

0-(0.5p^2-200)=0

We add all the numbers together, and all the variables

-(0.5p^2-200)=0

We get rid of parentheses

-0.5p^2+200=0

a = -0.5; b = 0; c = +200;
Δ = b2-4ac
Δ = 02-4·(-0.5)·200
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*-0.5}=\frac{-20}{-1}
=+20
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*-0.5}=\frac{20}{-1}
=-20
$