0=0.25x2-8x

Solution for 0=0.25x2-8x equation:

0=0.25x^2-8x

We move all terms to the left:

0-(0.25x^2-8x)=0

We add all the numbers together, and all the variables

-(0.25x^2-8x)=0

We get rid of parentheses

-0.25x^2+8x=0

a = -0.25; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-0.25)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-0.25}=\frac{-16}{-0.5}
=+32
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-0.25}=\frac{0}{-0.5}
=0
$