0=-4.9(x+3)(x-9)

Solution for 0=-4.9(x+3)(x-9) equation:

0=-4.9(x+3)(x-9)

We move all terms to the left:

0-(-4.9(x+3)(x-9))=0

We add all the numbers together, and all the variables

-(-4.9(x+3)(x-9))=0

We multiply parentheses ..

-(-4.9(+x^2-9x+3x-27))=0


We calculate terms in parentheses: -(-4.9(+x^2-9x+3x-27)), so:

-4.9(+x^2-9x+3x-27)

We multiply parentheses

-4.9x^2+44.1x-14.7x+132.3

We add all the numbers together, and all the variables

-4.9x^2+29.4x+132.3

Back to the equation:

-(-4.9x^2+29.4x+132.3)


We get rid of parentheses

4.9x^2-29.4x-132.3=0

a = 4.9; b = -29.4; c = -132.3;
Δ = b2-4ac
Δ = -29.42-4·4.9·(-132.3)
Δ = 3457.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29.4)-\sqrt{3457.44}}{2*4.9}=\frac{29.4-\sqrt{3457.44}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29.4)+\sqrt{3457.44}}{2*4.9}=\frac{29.4+\sqrt{3457.44}}{9.8}
$