0=-3x2+25x-16

Solution for 0=-3x2+25x-16 equation:

0=-3x^2+25x-16

We move all terms to the left:

0-(-3x^2+25x-16)=0

We add all the numbers together, and all the variables

-(-3x^2+25x-16)=0

We get rid of parentheses

3x^2-25x+16=0

a = 3; b = -25; c = +16;
Δ = b2-4ac
Δ = -252-4·3·16
Δ = 433
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{433}}{2*3}=\frac{25-\sqrt{433}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{433}}{2*3}=\frac{25+\sqrt{433}}{6}
$