0=-3(12-x)6x

Solution for 0=-3(12-x)6x equation:

0=-3(12-x)6x

We move all terms to the left:

0-(-3(12-x)6x)=0

We add all the numbers together, and all the variables

-(-3(-1x+12)6x)+0=0

We add all the numbers together, and all the variables

-(-3(-1x+12)6x)=0


We calculate terms in parentheses: -(-3(-1x+12)6x), so:

-3(-1x+12)6x

We multiply parentheses

18x^2-216x

Back to the equation:

-(18x^2-216x)


We get rid of parentheses

-18x^2+216x=0

a = -18; b = 216; c = 0;
Δ = b2-4ac
Δ = 2162-4·(-18)·0
Δ = 46656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{46656}=216$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(216)-216}{2*-18}=\frac{-432}{-36}
=+12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(216)+216}{2*-18}=\frac{0}{-36}
=0
$