0=-25t(t-8)

Solution for 0=-25t(t-8) equation:

0=-25t(t-8)

We move all terms to the left:

0-(-25t(t-8))=0

We add all the numbers together, and all the variables

-(-25t(t-8))=0


We calculate terms in parentheses: -(-25t(t-8)), so:

-25t(t-8)

We multiply parentheses

-25t^2+200t

Back to the equation:

-(-25t^2+200t)


We get rid of parentheses

25t^2-200t=0

a = 25; b = -200; c = 0;
Δ = b2-4ac
Δ = -2002-4·25·0
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-200}{2*25}=\frac{0}{50}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+200}{2*25}=\frac{400}{50}
=8
$