0=-2+2(1+3r)

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Solution for 0=-2+2(1+3r) equation: 



0=-2+2(1+3r)

We move all terms to the left:

0-(-2+2(1+3r))=0

We add all the numbers together, and all the variables

-(-2+2(3r+1))+0=0

We add all the numbers together, and all the variables

-(-2+2(3r+1))=0



We calculate terms in parentheses: -(-2+2(3r+1)), so:

-2+2(3r+1)

determiningTheFunctionDomain
2(3r+1)-2

We multiply parentheses

6r+2-2

We add all the numbers together, and all the variables

6r

Back to the equation:

-(6r)



r=0/-6

r=0

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