0=-16x2+216x+6

Solution for 0=-16x2+216x+6 equation:

0=-16x^2+216x+6

We move all terms to the left:

0-(-16x^2+216x+6)=0

We add all the numbers together, and all the variables

-(-16x^2+216x+6)=0

We get rid of parentheses

16x^2-216x-6=0

a = 16; b = -216; c = -6;
Δ = b2-4ac
Δ = -2162-4·16·(-6)
Δ = 47040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{47040}=\sqrt{3136*15}=\sqrt{3136}*\sqrt{15}=56\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-216)-56\sqrt{15}}{2*16}=\frac{216-56\sqrt{15}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-216)+56\sqrt{15}}{2*16}=\frac{216+56\sqrt{15}}{32}
$