0=-1.2x-0.36x2+5

Solution for 0=-1.2x-0.36x2+5 equation:

0=-1.2x-0.36x^2+5

We move all terms to the left:

0-(-1.2x-0.36x^2+5)=0

We add all the numbers together, and all the variables

-(-1.2x-0.36x^2+5)=0

We get rid of parentheses

0.36x^2+1.2x-5=0

a = 0.36; b = 1.2; c = -5;
Δ = b2-4ac
Δ = 1.22-4·0.36·(-5)
Δ = 8.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.2)-\sqrt{8.64}}{2*0.36}=\frac{-1.2-\sqrt{8.64}}{0.72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.2)+\sqrt{8.64}}{2*0.36}=\frac{-1.2+\sqrt{8.64}}{0.72}
$