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0=-0.024x^2+0.55x
We move all terms to the left:
0-(-0.024x^2+0.55x)=0
We add all the numbers together, and all the variables
-(-0.024x^2+0.55x)=0
We get rid of parentheses
0.024x^2-0.55x=0
a = 0.024; b = -0.55; c = 0;
Δ = b2-4ac
Δ = -0.552-4·0.024·0
Δ = 0.3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.55)-\sqrt{0.3025}}{2*0.024}=\frac{0.55-\sqrt{0.3025}}{0.048} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.55)+\sqrt{0.3025}}{2*0.024}=\frac{0.55+\sqrt{0.3025}}{0.048} $
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