0=-(15y-1)+24+2(5+5y)

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Solution for 0=-(15y-1)+24+2(5+5y) equation: 



0=-(15y-1)+24+2(5+5y)

We move all terms to the left:

0-(-(15y-1)+24+2(5+5y))=0

We add all the numbers together, and all the variables

-(-(15y-1)+24+2(5y+5))+0=0

We add all the numbers together, and all the variables

-(-(15y-1)+24+2(5y+5))=0



We calculate terms in parentheses: -(-(15y-1)+24+2(5y+5)), so:

-(15y-1)+24+2(5y+5)

determiningTheFunctionDomain
-(15y-1)+2(5y+5)+24

We multiply parentheses

-(15y-1)+10y+10+24

We get rid of parentheses

-15y+10y+1+10+24

We add all the numbers together, and all the variables

-5y+35

Back to the equation:

-(-5y+35)



We get rid of parentheses

5y-35=0

We move all terms containing y to the left, all other terms to the right

5y=35

y=35/5

y=7

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