0=(x+3)(x+5)+15

Solution for 0=(x+3)(x+5)+15 equation:

0=(x+3)(x+5)+15

We move all terms to the left:

0-((x+3)(x+5)+15)=0

We add all the numbers together, and all the variables

-((x+3)(x+5)+15)=0

We multiply parentheses ..

-((+x^2+5x+3x+15)+15)=0


We calculate terms in parentheses: -((+x^2+5x+3x+15)+15), so:

(+x^2+5x+3x+15)+15

We get rid of parentheses

x^2+5x+3x+15+15

We add all the numbers together, and all the variables

x^2+8x+30

Back to the equation:

-(x^2+8x+30)


We get rid of parentheses

-x^2-8x-30=0

We add all the numbers together, and all the variables

-1x^2-8x-30=0

a = -1; b = -8; c = -30;
Δ = b2-4ac
Δ = -82-4·(-1)·(-30)
Δ = -56
Delta is less than zero, so there is no solution for the equation