0=(x+16)(x-7)

Solution for 0=(x+16)(x-7) equation:

0=(x+16)(x-7)

We move all terms to the left:

0-((x+16)(x-7))=0

We add all the numbers together, and all the variables

-((x+16)(x-7))=0

We multiply parentheses ..

-((+x^2-7x+16x-112))=0


We calculate terms in parentheses: -((+x^2-7x+16x-112)), so:

(+x^2-7x+16x-112)

We get rid of parentheses

x^2-7x+16x-112

We add all the numbers together, and all the variables

x^2+9x-112

Back to the equation:

-(x^2+9x-112)


We get rid of parentheses

-x^2-9x+112=0

We add all the numbers together, and all the variables

-1x^2-9x+112=0

a = -1; b = -9; c = +112;
Δ = b2-4ac
Δ = -92-4·(-1)·112
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-23}{2*-1}=\frac{-14}{-2}
=+7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+23}{2*-1}=\frac{32}{-2}
=-16
$