0=(5x-4)(5x+4)

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Solution for 0=(5x-4)(5x+4) equation:


Simplifying
0 = (5x + -4)(5x + 4)

Reorder the terms:
0 = (-4 + 5x)(5x + 4)

Reorder the terms:
0 = (-4 + 5x)(4 + 5x)

Multiply (-4 + 5x) * (4 + 5x)
0 = (-4(4 + 5x) + 5x * (4 + 5x))
0 = ((4 * -4 + 5x * -4) + 5x * (4 + 5x))
0 = ((-16 + -20x) + 5x * (4 + 5x))
0 = (-16 + -20x + (4 * 5x + 5x * 5x))
0 = (-16 + -20x + (20x + 25x2))

Combine like terms: -20x + 20x = 0
0 = (-16 + 0 + 25x2)
0 = (-16 + 25x2)

Solving
0 = -16 + 25x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-25x2' to each side of the equation.
0 + -25x2 = -16 + 25x2 + -25x2
Remove the zero:
-25x2 = -16 + 25x2 + -25x2

Combine like terms: 25x2 + -25x2 = 0
-25x2 = -16 + 0
-25x2 = -16

Divide each side by '-25'.
x2 = 0.64

Simplifying
x2 = 0.64

Take the square root of each side:
x = {-0.8, 0.8}

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