0=(5a+4)(2-3a)

Solution for 0=(5a+4)(2-3a) equation:

0=(5a+4)(2-3a)

We move all terms to the left:

0-((5a+4)(2-3a))=0

We add all the numbers together, and all the variables

-((5a+4)(-3a+2))+0=0

We add all the numbers together, and all the variables

-((5a+4)(-3a+2))=0

We multiply parentheses ..

-((-15a^2+10a-12a+8))=0


We calculate terms in parentheses: -((-15a^2+10a-12a+8)), so:

(-15a^2+10a-12a+8)

We get rid of parentheses

-15a^2+10a-12a+8

We add all the numbers together, and all the variables

-15a^2-2a+8

Back to the equation:

-(-15a^2-2a+8)


We get rid of parentheses

15a^2+2a-8=0

a = 15; b = 2; c = -8;
Δ = b2-4ac
Δ = 22-4·15·(-8)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-22}{2*15}=\frac{-24}{30}
=-4/5
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+22}{2*15}=\frac{20}{30}
=2/3
$