0=(4/3)(-2)+b

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Solution for 0=(4/3)(-2)+b equation: 



0=(4/3)(-2)+b

We move all terms to the left:

0-((4/3)(-2)+b)=0



Domain of the equation: 3)(-2)+b)!=0

b∈R



We add all the numbers together, and all the variables

-((+4/3)(-2)+b)+0=0

We add all the numbers together, and all the variables

-((+4/3)(-2)+b)=0

We multiply parentheses ..

-(()+b)=0



We calculate terms in parentheses: -(()+b), so:

()+b

determiningTheFunctionDomain
b+()

We add all the numbers together, and all the variables

b

Back to the equation:

-(b)



b=0/-1

b=0

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