0=(3x-4)-(x-5)

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Solution for 0=(3x-4)-(x-5) equation: 



0=(3x-4)-(x-5)

We move all terms to the left:

0-((3x-4)-(x-5))=0

We add all the numbers together, and all the variables

-((3x-4)-(x-5))=0



We calculate terms in parentheses: -((3x-4)-(x-5)), so:

(3x-4)-(x-5)

We get rid of parentheses

3x-x-4+5

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We get rid of parentheses

-2x-1=0

We move all terms containing x to the left, all other terms to the right

-2x=1

x=1/-2

x=-1/2

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