0=(3x+6)(2x-10)

Solution for 0=(3x+6)(2x-10) equation:

0=(3x+6)(2x-10)

We move all terms to the left:

0-((3x+6)(2x-10))=0

We add all the numbers together, and all the variables

-((3x+6)(2x-10))=0

We multiply parentheses ..

-((+6x^2-30x+12x-60))=0


We calculate terms in parentheses: -((+6x^2-30x+12x-60)), so:

(+6x^2-30x+12x-60)

We get rid of parentheses

6x^2-30x+12x-60

We add all the numbers together, and all the variables

6x^2-18x-60

Back to the equation:

-(6x^2-18x-60)


We get rid of parentheses

-6x^2+18x+60=0

a = -6; b = 18; c = +60;
Δ = b2-4ac
Δ = 182-4·(-6)·60
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-42}{2*-6}=\frac{-60}{-12}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+42}{2*-6}=\frac{24}{-12}
=-2
$