0=(3-7i)(3-7i)

Solution for 0=(3-7i)(3-7i) equation:

0=(3-7i)(3-7i)

We move all terms to the left:

0-((3-7i)(3-7i))=0

We add all the numbers together, and all the variables

-((-7i+3)(-7i+3))+0=0

We add all the numbers together, and all the variables

-((-7i+3)(-7i+3))=0

We multiply parentheses ..

-((+49i^2-21i-21i+9))=0


We calculate terms in parentheses: -((+49i^2-21i-21i+9)), so:

(+49i^2-21i-21i+9)

We get rid of parentheses

49i^2-21i-21i+9

We add all the numbers together, and all the variables

49i^2-42i+9

Back to the equation:

-(49i^2-42i+9)


We get rid of parentheses

-49i^2+42i-9=0

a = -49; b = 42; c = -9;
Δ = b2-4ac
Δ = 422-4·(-49)·(-9)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{-42}{-98}=3/7$