0=(2y-1)(8y-y)

Solution for 0=(2y-1)(8y-y) equation:

0=(2y-1)(8y-y)

We move all terms to the left:

0-((2y-1)(8y-y))=0

We add all the numbers together, and all the variables

-((2y-1)(+7y))+0=0

We add all the numbers together, and all the variables

-((2y-1)(+7y))=0

We multiply parentheses ..

-((+14y^2-7y))=0


We calculate terms in parentheses: -((+14y^2-7y)), so:

(+14y^2-7y)

We get rid of parentheses

14y^2-7y

Back to the equation:

-(14y^2-7y)


We get rid of parentheses

-14y^2+7y=0

a = -14; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-14)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-14}=\frac{-14}{-28}
=1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-14}=\frac{0}{-28}
=0
$