0=(2x-4)-(-x1+9)

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Solution for 0=(2x-4)-(-x1+9) equation: 



0=(2x-4)-(-x1+9)

We move all terms to the left:

0-((2x-4)-(-x1+9))=0

We add all the numbers together, and all the variables

-((2x-4)-(-1x+9))+0=0

We add all the numbers together, and all the variables

-((2x-4)-(-1x+9))=0



We calculate terms in parentheses: -((2x-4)-(-1x+9)), so:

(2x-4)-(-1x+9)

We get rid of parentheses

2x+1x-4-9

We add all the numbers together, and all the variables

3x-13

Back to the equation:

-(3x-13)



We get rid of parentheses

-3x+13=0

We move all terms containing x to the left, all other terms to the right

-3x=-13

x=-13/-3

x=4+1/3

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