0=(2x+6)(8x-3)

Solution for 0=(2x+6)(8x-3) equation:

0=(2x+6)(8x-3)

We move all terms to the left:

0-((2x+6)(8x-3))=0

We add all the numbers together, and all the variables

-((2x+6)(8x-3))=0

We multiply parentheses ..

-((+16x^2-6x+48x-18))=0


We calculate terms in parentheses: -((+16x^2-6x+48x-18)), so:

(+16x^2-6x+48x-18)

We get rid of parentheses

16x^2-6x+48x-18

We add all the numbers together, and all the variables

16x^2+42x-18

Back to the equation:

-(16x^2+42x-18)


We get rid of parentheses

-16x^2-42x+18=0

a = -16; b = -42; c = +18;
Δ = b2-4ac
Δ = -422-4·(-16)·18
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-54}{2*-16}=\frac{-12}{-32}
=3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+54}{2*-16}=\frac{96}{-32}
=-3
$