0=(11-2x)(8.5-2x)

Solution for 0=(11-2x)(8.5-2x) equation:

0=(11-2x)(8.5-2x)

We move all terms to the left:

0-((11-2x)(8.5-2x))=0

We add all the numbers together, and all the variables

-((-2x+11)(-2x+8.5))+0=0

We add all the numbers together, and all the variables

-((-2x+11)(-2x+8.5))=0

We multiply parentheses ..

-((+4x^2-17x-22x+93.5))=0


We calculate terms in parentheses: -((+4x^2-17x-22x+93.5)), so:

(+4x^2-17x-22x+93.5)

We get rid of parentheses

4x^2-17x-22x+93.5

We add all the numbers together, and all the variables

4x^2-39x+93.5

Back to the equation:

-(4x^2-39x+93.5)


We get rid of parentheses

-4x^2+39x-93.5=0

a = -4; b = 39; c = -93.5;
Δ = b2-4ac
Δ = 392-4·(-4)·(-93.5)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-5}{2*-4}=\frac{-44}{-8}
=5+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+5}{2*-4}=\frac{-34}{-8}
=4+1/4
$