0=((9x-5)+(16-(9x-5))-16)

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Solution for 0=((9x-5)+(16-(9x-5))-16) equation: 



0=((9x-5)+(16-(9x-5))-16)

We move all terms to the left:

0-(((9x-5)+(16-(9x-5))-16))=0

We add all the numbers together, and all the variables

-(((9x-5)+(16-(9x-5))-16))=0



We calculate terms in parentheses: -(((9x-5)+(16-(9x-5))-16)), so:

((9x-5)+(16-(9x-5))-16)



We calculate terms in parentheses: +((9x-5)+(16-(9x-5))-16), so:

(9x-5)+(16-(9x-5))-16

We get rid of parentheses

9x+(16-(9x-5))-5-16



We calculate terms in parentheses: +(16-(9x-5)), so:

16-(9x-5)

determiningTheFunctionDomain
-(9x-5)+16

We get rid of parentheses

-9x+5+16

We add all the numbers together, and all the variables

-9x+21

Back to the equation:

+(-9x+21)



We add all the numbers together, and all the variables

9x+(-9x+21)-21

We get rid of parentheses

9x-9x+21-21

We add all the numbers together, and all the variables



Back to the equation:

+()



We add all the numbers together, and all the variables



Back to the equation:

-()



We add all the numbers together, and all the variables

=0

x=0/1

x=0

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