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07(x-1)=2(x+4)
We move all terms to the left:
07(x-1)-(2(x+4))=0
We multiply parentheses
7x-(2(x+4))-7=0
We calculate terms in parentheses: -(2(x+4)), so:We get rid of parentheses
2(x+4)
We multiply parentheses
2x+8
Back to the equation:
-(2x+8)
7x-2x-8-7=0
We add all the numbers together, and all the variables
5x-15=0
We move all terms containing x to the left, all other terms to the right
5x=15
x=15/5
x=3
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