05x2+70x+245=05,

Solution for 05x2+70x+245=05, equation:

05x^2+70x+245=05.

We move all terms to the left:

05x^2+70x+245-(05.)=0

We add all the numbers together, and all the variables

05x^2+70x+245-5=0

We add all the numbers together, and all the variables

05x^2+70x+240=0

a = 05; b = 70; c = +240;
Δ = b2-4ac
Δ = 702-4·05·240
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-10}{2*05}=\frac{-80}{10}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+10}{2*05}=\frac{-60}{10}
=-6
$