0/2(10-5c)=5c-16

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Solution for 0/2(10-5c)=5c-16 equation: 



0/2(10-5c)=5c-16

We move all terms to the left:

0/2(10-5c)-(5c-16)=0



Domain of the equation: 2(10-5c)!=0

c∈R



We add all the numbers together, and all the variables

0/2(-5c+10)-(5c-16)=0

We get rid of parentheses

0/2(-5c+10)-5c+16=0

We multiply all the terms by the denominator


-5c*2(-5c+10)+16*2(-5c+10)+0=0

We add all the numbers together, and all the variables

-5c*2(-5c+10)+16*2(-5c+10)=0

Wy multiply elements

-10c^2(-+32c(-=0

We use the square of the difference formula

-10c^2(-32c(-=0

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